Modulo M. For these cases there is an operator called the modulo operator (abbreviated as mod). The residues are added by finding the arithmetic sum of the numbers, and the mod is subtracted from the sum as many times as possible.

11 mod 5 has a remainder of 1.

So 1 = 7 − 2(3) = 7 − 2(31 − 4(7)) = 9(7) − 2(31). Congruence, modular arithmetic, 3 ways to interpret a ≡ b (mod n), number theory, discrete math, how to solve congruence, 💪 join our channel membership (for. A mod c = r1. A = b+km for some integer k.